Replace status prop with checked in ToggleButton component

**Is your feature request related to a problem? Please describe.**
The `ToggleButton` component currently uses a `status` prop with string values `checked` | `unchecked`. This adds unnecessary complexity for a binary state.

**Describe the solution you'd like**
Replace the `status` prop with a boolean `checked` prop.

Before:
```typescript
const ToggleButtonExample = () => {
const [status, setStatus] = React.useState('checked');

const onButtonToggle = () => {
setStatus(status === 'checked' ? 'unchecked' : 'checked');
};

return (

);
};
```

After:
```typescript
const ToggleButtonExample = () => {
const [isChecked, setIsChecked] = React.useState(true);

const onButtonToggle = () => {
setIsChecked(s => !s);
};

return (

);
};
```

**Additional context**
A boolean checked prop is simpler, clearer, and more consistent with common React patterns than using string values like 'checked' and 'unchecked'.

在 react-native-paper 代码库中找到 ToggleButton 的实现及其使用位置，然后检查当前 status prop 的类型定义和使用方式。当组件及其调用方都统一使用布尔值 checked，而不是 status 字符串值时，工作即完成。

由索引模型根据 Issue 内容生成。