Support Snowflake lambda functions

Snowflake recently gained support for [higher-order functions](https://medium.com/snowflake/snowflake-supports-higher-order-functions-dfa4b7682f7a) like [`TRANSFORM`](https://docs.snowflake.com/en/sql-reference/functions/transform) and [`FILTER`](https://docs.snowflake.com/en/sql-reference/functions/filter) which utilize a new [lambda function syntax](https://docs.snowflake.com/en/user-guide/querying-semistructured#lambda-expressions) similar to that of [Databricks](https://docs.databricks.com/en/sql/language-manual/sql-ref-lambda-functions.html) for which I [recently added support](https://github.com/sqlparser-rs/sqlparser-rs/pull/1257).

The two syntaxes look compatible so we can mostly reuse what we have. The one difference I noted is that Snowflake lambdas are permitted to specify types, e.g. `(x INT, y INT) -> (x + y)`.

まず、既存の Databricks lambda-function サポートと PR #1257 を確認し、その後、Snowflake の lambda-expression および higher-order-function の構文と比較します。`(x INT, y INT) -> (x + y)` のように明示的な型を持つパラメータを含め、Snowflake の lambda が正常にパースされ、既存の互換構文を壊さないことが完了条件です。

索引モデルが issue の本文から書いたものです。