Illegal "yield (from)" python syntax accepted

Originally reported as https://github.com/astral-sh/ruff/issues/4992.

I'm not quite sure where the incorrectness here is, but I think this bug indicates an incorrect parsing of the yield from expression. The following is a python snippet with illegal syntax:

def e():
  x = yield from y = 5

We can verify that it is indeed illegal syntax with:

$ python yield-elision.py 
  File "/tmp/tmp.1z4PScoI6T/yield-elision.py", line 2
    x = yield from y = 5
        ^^^^^^^^^^^^
SyntaxError: assignment to yield expression not possible

Ruff, however, believes this is valid syntax:

$ ruff yield-elision.py --show-source --show-fixes
yield-elision.py:2:3: F841 [*] Local variable `x` is assigned to but never used
  |
2 | def e():
3 |   x = yield from y = 5
  |   ^ F841
  |
  = help: Remove assignment to unused variable `x`

yield-elision.py:2:18: F821 Undefined name `y`
  |
2 | def e():
3 |   x = yield from y = 5
  |                  ^ F821
  |

Found 2 errors.

And will attempt to fix it, leading to a self-reported parsing error:

$ ruff yield-elision.py  --fix
error: Autofix introduced a syntax error in `yield-elision.py` with rule codes F841: invalid syntax. Got unexpected token '=' at byte offset 24
---
def e():
  yield from y = 5

---
yield-elision.py:2:3: F841 Local variable `x` is assigned to but never used
yield-elision.py:2:18: F821 Undefined name `y`
Found 2 errors.

I believe this indicates a parsing bug.

Bắt đầu bằng cách tái hiện ví dụ yield from trong issue và theo dõi cách parser xử lý biểu thức này. Công việc được xem là hoàn tất khi cú pháp Python không hợp lệ do Ruff báo cáo bị từ chối, thay vì được xử lý như mã hợp lệ hoặc tạo ra một autofix làm phát sinh lỗi cú pháp.