Illegal "yield (from)" python syntax accepted

Originally reported as https://github.com/astral-sh/ruff/issues/4992.

I'm not quite sure where the incorrectness here is, but I think this bug indicates an incorrect parsing of the yield from expression. The following is a python snippet with illegal syntax:

def e():
  x = yield from y = 5

We can verify that it is indeed illegal syntax with:

$ python yield-elision.py 
  File "/tmp/tmp.1z4PScoI6T/yield-elision.py", line 2
    x = yield from y = 5
        ^^^^^^^^^^^^
SyntaxError: assignment to yield expression not possible

Ruff, however, believes this is valid syntax:

$ ruff yield-elision.py --show-source --show-fixes
yield-elision.py:2:3: F841 [*] Local variable `x` is assigned to but never used
  |
2 | def e():
3 |   x = yield from y = 5
  |   ^ F841
  |
  = help: Remove assignment to unused variable `x`

yield-elision.py:2:18: F821 Undefined name `y`
  |
2 | def e():
3 |   x = yield from y = 5
  |                  ^ F821
  |

Found 2 errors.

And will attempt to fix it, leading to a self-reported parsing error:

$ ruff yield-elision.py  --fix
error: Autofix introduced a syntax error in `yield-elision.py` with rule codes F841: invalid syntax. Got unexpected token '=' at byte offset 24
---
def e():
  yield from y = 5

---
yield-elision.py:2:3: F841 Local variable `x` is assigned to but never used
yield-elision.py:2:18: F821 Undefined name `y`
Found 2 errors.

I believe this indicates a parsing bug.

Inizia riproducendo l'esempio yield from dell'issue e traccia il modo in cui il parser gestisce l'espressione. Il lavoro è completato quando la sintassi Python non valida segnalata da Ruff viene rifiutata, invece di essere trattata come codice valido o di produrre un autofix che introduce un errore di sintassi.