RustPython / RustPython/Parser

Illegal "yield (from)" python syntax accepted

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bug
主要语言
Rust
星标
117
派生
38
平均合并
4 天 7 小时
30 天内合并 PR
1

描述

Originally reported as https://github.com/astral-sh/ruff/issues/4992.

I'm not quite sure where the incorrectness here is, but I think this bug indicates an incorrect parsing of the yield from expression. The following is a python snippet with illegal syntax:

def e():
  x = yield from y = 5

We can verify that it is indeed illegal syntax with:

$ python yield-elision.py 
  File "/tmp/tmp.1z4PScoI6T/yield-elision.py", line 2
    x = yield from y = 5
        ^^^^^^^^^^^^
SyntaxError: assignment to yield expression not possible

Ruff, however, believes this is valid syntax:

$ ruff yield-elision.py --show-source --show-fixes
yield-elision.py:2:3: F841 [*] Local variable `x` is assigned to but never used
  |
2 | def e():
3 |   x = yield from y = 5
  |   ^ F841
  |
  = help: Remove assignment to unused variable `x`

yield-elision.py:2:18: F821 Undefined name `y`
  |
2 | def e():
3 |   x = yield from y = 5
  |                  ^ F821
  |

Found 2 errors.

And will attempt to fix it, leading to a self-reported parsing error:

$ ruff yield-elision.py  --fix
error: Autofix introduced a syntax error in `yield-elision.py` with rule codes F841: invalid syntax. Got unexpected token '=' at byte offset 24
---
def e():
  yield from y = 5

---
yield-elision.py:2:3: F841 Local variable `x` is assigned to but never used
yield-elision.py:2:18: F821 Undefined name `y`
Found 2 errors.

I believe this indicates a parsing bug.

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调研方向

首先重现 issue 中的 yield from 示例,并跟踪 parser 如何处理该表达式。完成的标准是:Ruff 报告的无效 Python 语法会被拒绝,而不是被当作有效代码处理,或生成引入语法错误的 autofix。

由索引模型根据 Issue 内容生成。

评估

技术栈
python, rust
领域
compilers
Issue 类型
缺陷
难度
4/5
预计耗时
3-5 天
活跃度
停滞
描述清晰度
描述清楚
新手友好度
45/100

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