JuliaPy / JuliaPy/PythonCall.jl
how to optimize reading long tuples from julia to python
- 主要言語
- Julia
- スター
- 1.1k
- フォーク
- 86
- 平均マージ
- 1日 22時間
- マージ済み PR(30日)
- 3
説明
**Is your feature request related to a problem? Please describe.**
This code takes around 7s on a modern i9 the first time that it's executed. It's immediate the next times it's executed. It's also immediate to execute `(zeros(20_000)...,)` in julia.
I have python 3.12 and julia 1.10.5
```python
import juliacall
v=juliacall.Main.seval("(zeros(20_000)...,)");
```
**Describe the solution you'd like**
Is there any way to speed up the initial compilation?
**Describe alternatives you've considered**
I tried to use this code to to speed up reading data from julia to python by going through a tuple. Looping a long julia vector from python is much slower than looping a tuple ( around 4 times slower to read a 100_000 floats vector vs reading a tuple)
コントリビューションガイド
このリポジトリのコントリビューションガイドは索引されていません
調査の方向性
Start by reproducing the juliacall.Main.seval example with Python 3.12 and Julia 1.10.5, measuring first-run and subsequent-run times for the long tuple and vector cases. Trace the tuple conversion and compilation path, then compare the results against the reported 7-second startup and four-times-slower vector iteration; done should be a verified optimization or a documented technical limitation.
索引モデルが issue の本文から書いたものです。
評価
- 技術スタック
- julia, python
- 領域
- performance
- issue の種類
- 機能追加
- 難易度
- 4/5
- 見積もり時間
- 3〜5日
- 活発さ
- 停滞
- 明瞭さ
- 説明が足りない
- 初心者へのやさしさ
- 35/100