JuliaPy / JuliaPy/PythonCall.jl

how to optimize reading long tuples from julia to python

未关闭
#575 6 条评论 0 个 reaction 已指派 0 人 在 GitHub 查看
enhancement
主要语言
Julia
星标
1.1k
派生
86
平均合并
1 天 22 小时
30 天内合并 PR
3

描述

**Is your feature request related to a problem? Please describe.**
This code takes around 7s on a modern i9 the first time that it's executed. It's immediate the next times it's executed. It's also immediate to execute `(zeros(20_000)...,)` in julia.
I have python 3.12 and julia 1.10.5
```python
import juliacall
v=juliacall.Main.seval("(zeros(20_000)...,)");
```

**Describe the solution you'd like**
Is there any way to speed up the initial compilation?

**Describe alternatives you've considered**
I tried to use this code to to speed up reading data from julia to python by going through a tuple. Looping a long julia vector from python is much slower than looping a tuple ( around 4 times slower to read a 100_000 floats vector vs reading a tuple)

贡献指南

这个仓库没有索引到贡献指南

调研方向

Start by reproducing the juliacall.Main.seval example with Python 3.12 and Julia 1.10.5, measuring first-run and subsequent-run times for the long tuple and vector cases. Trace the tuple conversion and compilation path, then compare the results against the reported 7-second startup and four-times-slower vector iteration; done should be a verified optimization or a documented technical limitation.

由索引模型根据 Issue 内容生成。

评估

技术栈
julia, python
领域
performance
Issue 类型
功能
难度
4/5
预计耗时
3-5 天
活跃度
停滞
描述清晰度
需要澄清
新手友好度
35/100

把新 issue 发到你的邮箱

精选适合新手参与的 GitHub issue 摘要。