JuliaPy / JuliaPy/PythonCall.jl

how to optimize reading long tuples from julia to python

Abierto
#575 6 comentarios 0 reacciones 0 asignados Ver en GitHub
enhancement
Lenguaje dominante
Julia
Estrellas
1.1k
Forks
86
Merge medio
1 d 22 h
PR fusionados (30 d)
3

Descripción

**Is your feature request related to a problem? Please describe.**
This code takes around 7s on a modern i9 the first time that it's executed. It's immediate the next times it's executed. It's also immediate to execute `(zeros(20_000)...,)` in julia.
I have python 3.12 and julia 1.10.5
```python
import juliacall
v=juliacall.Main.seval("(zeros(20_000)...,)");
```

**Describe the solution you'd like**
Is there any way to speed up the initial compilation?

**Describe alternatives you've considered**
I tried to use this code to to speed up reading data from julia to python by going through a tuple. Looping a long julia vector from python is much slower than looping a tuple ( around 4 times slower to read a 100_000 floats vector vs reading a tuple)

Guía de contribución

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Línea de trabajo

Start by reproducing the juliacall.Main.seval example with Python 3.12 and Julia 1.10.5, measuring first-run and subsequent-run times for the long tuple and vector cases. Trace the tuple conversion and compilation path, then compare the results against the reported 7-second startup and four-times-slower vector iteration; done should be a verified optimization or a documented technical limitation.

Escrito por el modelo de indexación a partir del texto del issue.

Evaluación

Stack tecnológico
julia, python
Área
performance
Tipo de issue
Nueva funcionalidad
Dificultad
4/5
Tiempo estimado
3-5 días
Estado de actividad
Estancado
Claridad
Necesita aclaración
Aptitud para principiantes
35/100

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