Covariant type variable error in nested function

I believe the below code should be allowed:

from typing import *

T_co = TypeVar('T_co', covariant=True)

class Col(Generic[T_co]):
  def __init__(self, items: Iterable[T_co]) -> None:
    self.items = items

  def any(self, pred: Callable[[T_co], bool]) -> bool:
    return any(map(pred, self.items))

  def any_zero(self, fn: Callable[[T_co], int]) -> bool:
    def pred(x: T_co) -> bool: # error: Cannot use type variable as a parameter
      return fn(x) == 0
    return self.any(pred)

I believe the purpose of this error is to disallow breaking variance, e.g.:

  def unsafe(self) -> Callable[[T_co], int]:
    def fn(t: T_co) -> int:
      return id(t)
    return fn

However, restricting variance on nested functions has both false positives (first example), and false negatives:

class Unsafe(Generic[T_co]):
  def __init__(self, fn: Callable[[T_co], int]) -> None:
    self.fn = fn

  def get_fn(self) -> Callable[[T_co], int]:
    return self.fn

The above code has no error, but is not type safe. I believe the proper way to check for this is to look at the signatures of each exposed method and verify that the type parameter is not used with the wrong parity.

mypy 0.740, python 3.7.5

まず、mypy 0.740 でネストされた関数の例を再現し、報告された変性エラーを安全でない公開メソッドの例と比較します。ネストされた関数と公開メソッドシグネチャに対する変性チェックを追跡します。安全な例が受け入れられ、安全でないケースが偽陰性を導入せずに拒否されれば完了です。