Relax `PyUnstable_SetImmortal` to objects allocated in that thread?
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Từ ngày 7/9/2026.
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Mô tả
Feature or enhancement
Proposal:
Currently PyUnstable_SetImmortal requires a uniquely referenced object. I think the docs could be a bit clearer about this but that isn't the tricky part.
The tricky part is that I think it doesn't seem uncommon to create objects which are not uniquely referenced. I have two overlapping places in NumPy where I was hope to use this while making types that were previously static to heaptypes:
- If you have non-trivial setup code that might fail you want to immortalize at the very end. In my case I wanted to add the object to a dict (as a last step). (Sure, if I am going to immortalize it, then I can re-order adding it to the dict with a lock or so.)
- I am using
PyType_FromMetaType()and the returned object already has 3 references when created fresh.
Basically, I get the "err on the safe side" part, but from poking it a bit and looking at https://github.com/python/cpython/issues/113956 it seems that the real limitation seems to be that the current thread owns the object.
Ensuring the object is created on the current thread is trivial no matter how complicated object creation itself is.
CC @ngoldbaum
Has this already been discussed elsewhere?
No response given
Links to previous discussion of this feature:
No response
Linked PRs
- gh-150956
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