Wrong binding of closure variable with intervening list comprehension

Bug report

Bug description:

def f(x):
    def g():
        print([x for x in range(10)])
        def h():
            print(x)
        return h
    print(x)
    return g
f(1)()()

The above had always bound x in h to the parameter of f. But it no longer works and somehow binds to a local in g, throwing the following error:

NameError: cannot access free variable 'x' where it is not associated with a value in enclosing scope

CPython versions tested on:

3.12

Operating systems tested on:

Linux, Windows

Linked PRs

• gh-124696

在 CPython 3.12 上重現 closure 和列表推導式範例，並將其輸出與回報的 NameError 進行比較。先檢視該範例涉及的作用域和編譯路徑，然後檢查關聯的 PR gh-124696。當範例將 x 繫結至 f 的參數並在沒有該錯誤的情況下完成時，即表示完成。