Wrong binding of closure variable with intervening list comprehension

Bug report

Bug description:

def f(x):
    def g():
        print([x for x in range(10)])
        def h():
            print(x)
        return h
    print(x)
    return g
f(1)()()

The above had always bound x in h to the parameter of f. But it no longer works and somehow binds to a local in g, throwing the following error:

NameError: cannot access free variable 'x' where it is not associated with a value in enclosing scope

CPython versions tested on:

3.12

Operating systems tested on:

Linux, Windows

Linked PRs

• gh-124696

在 CPython 3.12 上重现 closure 和列表推导式示例，并将其输出与报告的 NameError 进行比较。首先检查该示例涉及的作用域和编译路径，然后检查关联的 PR gh-124696。当示例将 x 绑定到 f 的参数并在没有该错误的情况下完成时，即视为完成。