Wrong inference for defaulted generic in nested call

Nessuno ha ancora preso questa issue.

### 🔎 Search Terms

nested generic call inline inference contextual typing function calls default type parameter

### 🕗 Version & Regression Information

- I see the same issue from version 4.1.5 to nightly in TypeScript Playground

### ⏯ Playground Link

https://www.typescriptlang.org/play/?ts=6.0.0-dev.20260401#code/CYUwxgNghgTiAEAzArgOzAFwJYHtXwCsctUAeAFXhAA8MRVgBneRjGEgcwBp4BVK2vSYs2nHgDUBdBs1btUHeAF54AclUA+ABStYGAFzxyPIYd49GIAA4B+Q+ICUhgAYASAN7kAvh-E-3vF7OAFCgkLAIKOjYeAJW4BgU2gBuUBDIIIbkTvDu8Bg4AEIgWjTxmCDAWTnJxMDwXsHBZQlaRCRaqgASIBAQOKo8qgDqODAQwKoODgB0BcWdPX04o+OTDvAA9JvwAEZQwE1geKzwAO5YGAAWOMgYAMrWsFAFMMqExKiLvf2DaqsTKbBbbwUHwAB6Nma1HKGC0F2utweTxgLzGs3mJQAREt+gDgFiNiCODgcIdobC2p9vss-iMxoChmppnMiiVuj8cPB8VMtjsSWTgkA

### 💻 Code

```ts
declare function join(start: T, end: U, sep?: V): `${T}${V}${U}`
declare function expect(value: T): { toBe(expected: T): void }

expect(join('Hello', 'World')).toBe('HelloWorld') // bad

const withoutSeparator = join('Hello', 'World')
// ^? const withoutSeparator: "HelloWorld"
expect(withoutSeparator).toBe("HelloWorld") // good

expect(join('Hello', 'World', ' ')).toBe('Hello World') // good
```

### 🙁 Actual behavior

TypeScript does not infer the return types correctly of a nested function call when an optional generic param is omitted, even if a default is provided. When the function call is not nested, it is inferred correctly. It is also inferred correctly when all params are provided.

### 🙂 Expected behavior

I would expect that both of these approaches would compile:

```ts
expect(join('Hello', 'World')).toBe('HelloWorld') // bad

const withoutSeparator = join('Hello', 'World')
expect(withoutSeparator).toBe("HelloWorld") // good
```

### Additional information about the issue

There are very similar issues, such as #54184, #56714, and #62680 but they didn't quite match up to what I'm seeing here, particularly since the reproductions are quite a bit more complex.

Inizia eseguendo la riproduzione collegata in TypeScript Playground e confronta la chiamata annidata con le chiamate autonoma e completamente specificata. Leggi le issue correlate #54184, #56714 e #62680 per il contesto di inferenza esistente. Il lavoro è completato quando entrambi gli esempi senza separatore specificato vengono compilati con il tipo letterale previsto, mentre il caso con separatore fornito rimane corretto.

Scritto dal modello di indicizzazione a partire dal testo della issue.