Comparing arrays doesn't give any error

まだ誰も着手していません。

### 🔎 Search Terms

Arrays, Compare, Less than, Greater than

### 🕗 Version & Regression Information

- This is the behavior in every version I tried, and I reviewed the FAQ for entries about arrays and comparisons

### ⏯ Playground Link

https://www.typescriptlang.org/play/?ts=5.8.3#code/MYewdgzgLgBAhjAvDA2gIjgIzQGhm4HAEzQF0AoUSWTJVDTHYXfZiqiEAGwFMA6LiADmACgQA+ZJgCUQA

### 💻 Code

```ts
const a = [11, 12, 13]
const b = [4, 5]
console.log(a >= b)
```

### 🙁 Actual behavior

This compiles without any error, returning a potentially unexpected result at runtime.

### 🙂 Expected behavior

This should give an error. Maybe something like TS2365 "Operator '>=' cannot be applied to types 'number[]' and 'number[]'".

### Additional information about the issue

What this code actually does at runtime is that first it converts the arrays to strings, then compares the resulting strings by alphabetical order. I'm quite sure this is almost never intended/useful.

Anyone coming from languages like Python or C++ would expect the arrays to be compared lexicographically, which isn't the case here. And in my specific case I actually intended to compare the lengths of the array (and simply forgot to write `.length`), and not getting a compile time error here led to a bug in my program.

まず、リンクされた TypeScript Playground で、提供された配列比較を使って挙動を再現します。次に、型チェッカーが関係演算子と配列型をどのように処理するかを追跡します。完了とは、サポートされている比較を壊すことなく、issue が要求する診断動作が回帰テストでカバーされていることを意味します。

索引モデルが issue の本文から書いたものです。