Comparing arrays doesn't give any error

🔎 Search Terms

Arrays, Compare, Less than, Greater than

🕗 Version & Regression Information

• This is the behavior in every version I tried, and I reviewed the FAQ for entries about arrays and comparisons

⏯ Playground Link

https://www.typescriptlang.org/play/?ts=5.8.3#code/MYewdgzgLgBAhjAvDA2gIjgIzQGhm4HAEzQF0AoUSWTJVDTHYXfZiqiEAGwFMA6LiADmACgQA+ZJgCUQA

💻 Code

const a = [11, 12, 13]
const b = [4, 5]
console.log(a >= b)

🙁 Actual behavior

This compiles without any error, returning a potentially unexpected result at runtime.

🙂 Expected behavior

This should give an error. Maybe something like TS2365 "Operator '>=' cannot be applied to types 'number[]' and 'number[]'".

Additional information about the issue

What this code actually does at runtime is that first it converts the arrays to strings, then compares the resulting strings by alphabetical order. I'm quite sure this is almost never intended/useful.

Anyone coming from languages like Python or C++ would expect the arrays to be compared lexicographically, which isn't the case here. And in my specific case I actually intended to compare the lengths of the array (and simply forgot to write .length), and not getting a compile time error here led to a bug in my program.

Empieza reproduciendo el comportamiento en el TypeScript Playground enlazado con la comparación de arrays proporcionada. Después, sigue cómo el comprobador de tipos gestiona los operadores relacionales y los tipos de array. Se considerará completado cuando el comportamiento de diagnóstico solicitado por el issue esté cubierto por una prueba de regresión sin romper las comparaciones compatibles.