Generated d.ts includes implicit any for recursive types

🔎 Search Terms

recursive any noImplicitAny d.ts

🕗 Version & Regression Information

• This is the behavior in every version I tried (3.3 through 5.2), and I reviewed the FAQ for entries about anything related to this.

⏯ Playground Link

playground link

💻 Code

const a = () => a;

🙁 Actual behavior

Any is implicitly introduced in the d.ts:

declare const a: () => any;

Note that the local type checking (not using the d.ts) correctly handles this recursive type without introducing "any", and builds fine with noImplicitAny enabled.

🙂 Expected behavior

Either generate something without implicitly introducing any, or generate an error if noImplicitAny is enabled.
In this case, the below code generation for the d.ts would work:

declare const a: () => typeof a;

Additional information about the issue

No response

リンクされた Playground の再現から始め、const a = () => a に対して生成される宣言を、期待される typeof a 形式と比較します。この再帰型の宣言生成パスを追跡し、noImplicitAny の回帰テストを追加または更新します。再帰宣言で暗黙の any が導入されなくなるか、適切なエラーが報告されれば完了です。