Generated d.ts includes implicit any for recursive types

🔎 Search Terms

recursive any noImplicitAny d.ts

🕗 Version & Regression Information

• This is the behavior in every version I tried (3.3 through 5.2), and I reviewed the FAQ for entries about anything related to this.

⏯ Playground Link

playground link

💻 Code

const a = () => a;

🙁 Actual behavior

Any is implicitly introduced in the d.ts:

declare const a: () => any;

Note that the local type checking (not using the d.ts) correctly handles this recursive type without introducing "any", and builds fine with noImplicitAny enabled.

🙂 Expected behavior

Either generate something without implicitly introducing any, or generate an error if noImplicitAny is enabled.
In this case, the below code generation for the d.ts would work:

declare const a: () => typeof a;

Additional information about the issue

No response

Comienza con la reproducción vinculada en Playground y compara la declaración generada para const a = () => a con la forma esperada de typeof a. Rastrea la ruta de generación de declaraciones para este tipo recursivo y añade o actualiza una prueba de regresión para noImplicitAny. Se considera terminado cuando las declaraciones recursivas ya no introducen any implícito o se informa de un error apropiado.