Allow a type annotation for indicating the type of a destructured rest assignment

Suggestion

I offer allow to assign type to rest in destructuring assignment.

🔍 Search Terms

destructuring assignment, desctructuring, rest

✅ Viability Checklist

My suggestion meets these guidelines:

• This wouldn't be a breaking change in existing TypeScript/JavaScript code
• This wouldn't change the runtime behavior of existing JavaScript code
• This could be implemented without emitting different JS based on the types of the expressions
• This isn't a runtime feature (e.g. library functionality, non-ECMAScript syntax with JavaScript output, new syntax sugar for JS, etc.)
• This feature would agree with the rest of TypeScript's Design Goals.

⭐ Suggestion

const { e, ...rest }: { e: number, ...rest: ICalculatedNumbers } = test;

For better understanding please check Use Cases

📃 Motivating Example

I wanted to assign new calculated value to destructured assigment to field that moved out to new variable by destructuring, but I can't do it because new type exists without field and I'm not able to assign new type to desctructuring assignment.

Provided example in Use Cases

💻 Use Cases

Current behavior in TypeScript

export interface INumbersE {
    c: number;
    d: number;
}

export interface INumbers {
    a?: number;
    b?: number;
    c?: number;
    d?: number;
    e?: INumbersE;
}

export interface ICalculatedNumbers {
    a?: number;
    b?: number;
    c?: number;
    d?: number;
    e?: number;
}

const calcTheNumber = (numbers: ICalculatedNumbers) => {
    // another logic goes there
    console.log(numbers);
}

const test: INumbers = {
    a: 1,
    b: 2,
    c: 3,
    d: 4,
    e: {
        c: 2,
        d: 3
    }
};


const { e, ...rest }: { e: number, ...rest: ICalculatedNumbers } = test; // Property 'rest' is missing in type 'INumbers' but required in type '{ e: number; rest: ICalculatedNumbers; }'

if (e && e.c + e.d === 5) { // Property 'd' does not exist on type 'number' || Property 'c' does not exist on type 'number'
    rest.e = 5; // Property 'e' does not exist on type '{ a: number; b: number; c: number; d: number; }'
}

calcTheNumber(rest); // Type '{ rest: ICalculatedNumbers; }' has no properties in common with type 'ICalculatedNumbers'.

Running in pure JS right as expected behavior and getting expected object with e: 5

const test = {
    a: 1,
    b: 2,
    c: 3,
    d: 4,
    e: {
        c: 2,
        d: 3
    }
};

const calcTheNumber = (numbers) => {
    console.log(numbers); // { a: 1, b: 2, c: 3, d: 4, e: 5 }
}

const { e, ...rest } = test;

if (e && e.c + e.d === 5) {
    rest.e = 5;
}

calcTheNumber(rest);

If cover errors with //@ts-ignore, it'll run as expected, but I'm not ok with that.

Aucun fichier, test ou point d’entrée n’est nommé. Commencez par examiner la syntaxe d’annotation destructuring-rest proposée et les exemples motivants ; le travail est terminé lorsque le comportement prévu de vérification des types est convenu et couvert par des tests du compilateur.