Parentheses in nullish coalescing chains impacts type narrowing

Bug Report

🔎 Search Terms

nullish coalescing chain parentheses type narrowing prettier

🕗 Version & Regression Information

This is the behavior in every version I tried, and I reviewed the FAQ for entries about nullish coalescing. Note that at the time of writing, 4.3.5 was the latest stable release.

⏯ Playground Link

Playground link with relevant code

💻 Code

type T =
  | { a: string; b: string }
  | { a: string; b?: undefined }
  | { a?: undefined; b: string };

const getResult1 = (value1: string | undefined, value2: T): string => {
  return value1 ?? value2.a ?? value2.b;
};

const getResult2 = (value1: string | undefined, value2: T): string => {
  return value1 ?? (value2.a ?? value2.b);
};

🙁 Actual behavior

• getResult1 throws a type error, as TypeScript incorrectly infers that value2.b has a type of string | undefined.
• getResult2 does not throw a type error, as TypeScript correctly infers that value2.b has a type of string.

🙂 Expected behavior

The existence and placement of parentheses in nullish coalescing chains should not impact type narrowing, as to my knowledge (and prettier, as it automatically removes the parentheses seen in getResult2), x ?? y ?? z and x ?? (y ?? z) actually behave the same at runtime.

Comienza con la reproducción vinculada en TypeScript Playground y compara los diagnósticos de getResult1 y getResult2. Traza cómo las cadenas de nullish coalescing y las expresiones entre paréntesis afectan al estrechamiento de tipos; después, añade una prueba de regresión que cubra ambas formas equivalentes. Se considera terminado cuando ambas formas infieren value2.b como string y producen el mismo resultado aceptado.