Encrypting the entire table is impossible

```java

public InternalColumnEncryptionSetup getColumnSetup(ColumnPath columnPath,
boolean createIfNull, int ordinal) {
InternalColumnEncryptionSetup internalColumnProperties = columnMap.get(columnPath);

if (null != internalColumnProperties) {
if (ordinal != internalColumnProperties.getOrdinal()) {
throw new ParquetCryptoRuntimeException("Column ordinal doesnt match " + columnPath +
": " + ordinal + ", "+internalColumnProperties.getOrdinal());
}
return internalColumnProperties;
}

------ here is always true, then throw Exception
if (!createIfNull) {
throw new ParquetCryptoRuntimeException("No encryption setup found for column " + columnPath);
}
if (fileCryptoMetaDataCreated) {
throw new ParquetCryptoRuntimeException("Re-use: No encryption setup for column " + columnPath);
}

```

**Environment**: Linux
**Reporter**: [ren shangtao](https://issues.apache.org/jira/secure/ViewProfile.jspa?name=renshangtao)

_{**Note**: *This issue was originally created as [PARQUET-2174](https://issues.apache.org/jira/browse/PARQUET-2174). Please see the [migration documentation](https://issues.apache.org/jira/browse/PARQUET-2502) for further details.*}

Inizia tracciando getColumnSetup(ColumnPath, boolean, int) e la ricerca in columnMap mostrata nell’issue. Riproduci il percorso segnalato in cui il controllo di createIfNull causa un’eccezione, quindi verifica che la crittografia dell’intera tabella non fallisca più in quel caso.

Scritto dal modello di indicizzazione a partire dal testo della issue.