Encrypting the entire table is impossible

```java

public InternalColumnEncryptionSetup getColumnSetup(ColumnPath columnPath,
boolean createIfNull, int ordinal) {
InternalColumnEncryptionSetup internalColumnProperties = columnMap.get(columnPath);

if (null != internalColumnProperties) {
if (ordinal != internalColumnProperties.getOrdinal()) {
throw new ParquetCryptoRuntimeException("Column ordinal doesnt match " + columnPath +
": " + ordinal + ", "+internalColumnProperties.getOrdinal());
}
return internalColumnProperties;
}

------ here is always true, then throw Exception
if (!createIfNull) {
throw new ParquetCryptoRuntimeException("No encryption setup found for column " + columnPath);
}
if (fileCryptoMetaDataCreated) {
throw new ParquetCryptoRuntimeException("Re-use: No encryption setup for column " + columnPath);
}

```

**Environment**: Linux
**Reporter**: [ren shangtao](https://issues.apache.org/jira/secure/ViewProfile.jspa?name=renshangtao)

_{**Note**: *This issue was originally created as [PARQUET-2174](https://issues.apache.org/jira/browse/PARQUET-2174). Please see the [migration documentation](https://issues.apache.org/jira/browse/PARQUET-2502) for further details.*}

Comienza siguiendo getColumnSetup(ColumnPath, boolean, int) y la búsqueda en columnMap mostrada en el issue. Reproduce la ruta indicada en la que la comprobación de createIfNull provoca una excepción y, a continuación, verifica que cifrar la tabla completa ya no falle en ese caso.

Escrito por el modelo de indexación a partir del texto del issue.