[Docs] React.cloneElement and forwarding ref

Hi, I believe the documentation about React.cloneElement is not very clear about handling refs.

I am talking about that part: https://reactjs.org/docs/react-api.html#cloneelement

However, it also preserves refs. This means that if you get a child with a ref on it, you won’t accidentally steal it from your ancestor. You will get the same ref attached to your new element.

Now, let's see consider the following use case (simplified):

const ChangeTitle = ({ children, ...otherProps }) =>
  React.cloneElement(children, { 
    ...otherProps, 
    title: 'Title was changed'
  })

function MyComponent() {
  const myRef = React.useRef()
  return (
    <ChangeTitle ref={myRef}>
      <span>This is my component</span>
    </ChangeTitle>
  )
}

This throws a console warning about ChangeTitle unable to hold a ref.

In my original understanding of the docs, I though ChangeTitle would become the cloned element, which, as the docs explains, retain it's original ref, hance the one given by Mycomponent.

Instead, this is obviously wrong, and the cloned element would only retain a ref if it was given to itself, not the parent component, hence something like <span ref={spanRef}>This is my component</span>.

I guess the fix to the above code is the following:

const ChangeTitle = React.forwardRef(({ children, ...otherProps }, ref) =>
  React.cloneElement(children, { 
    ...otherProps, 
    ref,
    title: 'Title was changed'
  }))

Correct?

Is it worth adding specifically that cloneElement can contain the ref prop if used with React.forwardRef in a functional component?

Überprüfe den im Issue verlinkten Abschnitt zur React API cloneElement und vergleiche die Formulierung zu ref mit dem bereitgestellten ChangeTitle-Beispiel. Kläre, welcher ref beibehalten wird und wie React.forwardRef einen ref durchreichen kann; abgeschlossen ist die Aufgabe, wenn die Erklärung die Warnung und die korrigierte Verwendung准确 beschreibt.