(🐞) `overload`s that exhaust finite `Literal`s(`bool`/`Enum`) not treated as exhaustive

@overload
def foo(a: Literal[True]) -> int: ...

@overload
def foo(a: Literal[False]) -> str: ...

def foo(a: bool) -> object: ...

a: bool
reveal_type(foo(a))  # error: No overload variant of "foo" matches argument type "bool"

@overload
def foo(a: Literal[True]) -> int: ...

@overload
def foo(a: Literal[False]) -> str: ...

@overload
def foo(a: bool) -> object: ...  # no error regarding impossible to match overload

a: bool
reveal_type(foo(a))  # object

@overload
def foo(a: Literal[True, False]) -> int | str: ...

@overload
def foo(a: bool) -> object: ...  # error: Overloaded function signature 2 will never be matched: signature 1's parameter type(s) are the same or broader

def foo(a: bool) -> object: ...

a: bool
reveal_type(foo(a))  # int | str

Here mypy incorrectly forces us to implement a completely redundant overload for the non Literal case when it is already exhaustively covered by both literals. It is only when the literals are in the same overload (useless in practice, but just for demonstration) that mypy correctly handles this case.

Mypy should be doing 'union math' (or what ever it's called) to apply both literal overloads at once.

This also affects all other exhaustible Literals such as Enums.

This example is pulled directly from the docs, so I think they should be updated as well to an example that doesn't contain this confusing defect.

まず issue にある overload の例を再現し、リンクされた Literal types のドキュメントを読んでください。mypy による overload のマッチングと、有限個の Literal および Enum の値の扱いを追跡してください。すべてのケースを網羅する個別の Literal overload が、冗長な非 Literal overload をもはや必要とせず、影響を受けるドキュメント例が更新されれば完了です。