`asyncio.print_call_graph()` loses the call stack at asynchronous generators

Bug report

Bug description:

asyncio.print_call_graph() stops at the first async gen in the await chain and silently drops all of the call stack below it

Repro:

import asyncio

async def deep():
    await asyncio.Event().wait()

async def producer():
    await deep()
    yield 1

async def consumer():
    async for _ in producer():
        pass

async def main():
    t = asyncio.create_task(consumer(), name='consumer')
    await asyncio.sleep(0.05)
    print(asyncio.format_call_graph(t))

asyncio.run(main())

Expected:

* Task(name='consumer', id=0x105be89b0)
  + Call stack:
  |   File '/Users/timofeiivankov/cpython/Lib/asyncio/locks.py', line 210, in async Event.wait()
  |   File '/Users/timofeiivankov/cpython/repro.py', line 4, in async deep()
  |   File '/Users/timofeiivankov/cpython/repro.py', line 7, in async generator producer()
  |   File '/Users/timofeiivankov/cpython/repro.py', line 11, in async consumer()

Actual:

* Task(name='consumer', id=0x105b089b0)
  + Call stack:
  |   File '/Users/timofeiivankov/cpython/repro.py', line 11, in async consumer()

Proposed fix: expose the wrapped generator as ag_gen and step over the wrapper through it

Have a fix ready for that

CPython versions tested on:

CPython main branch

Operating systems tested on:

macOS

Linked PRs

• gh-156984

asyncio.format_call_graph() と issue の reproducer から始め、非同期ジェネレーター producer() と consumer task を含めます。コールグラフが await チェーンをどのようにたどるかを確認し、その出力を期待されるスタックと比較します。出力が非同期ジェネレーターより下のフレームを保持すれば完了です。リンクされている PR gh-156984 は、すでに作業が進行中であることを示しています。