`ZipFile.testzip()` Skips Earlier Duplicate Members
還沒有人認領這個 Issue。
- 主要語言
- Python
- 星號
- 77.2k
- 分支
- 36k
- PR 合併指標
- PR 指標待擷取
描述
Bug report
Summary
ZipFile.testzip() can incorrectly report that an archive is valid when an earlier member is corrupt and a later member has the same filename. The method iterates over all ZipInfo objects, but opens each one by filename instead of by its ZipInfo instance. Filename lookup selects the last duplicate, so earlier duplicates are checked against the wrong archive entry.
Minimal Reproducer
import io
import struct
import zipfile
buffer = io.BytesIO()
with zipfile.ZipFile(buffer, "w") as zf:
zf.writestr("duplicate.txt", b"corrupt me")
zf.writestr("duplicate.txt", b"valid data")
raw = bytearray(buffer.getvalue())
# Corrupt the payload of the first duplicate only.
with zipfile.ZipFile(io.BytesIO(raw)) as zf:
first = zf.infolist()[0]
name_length, extra_length = struct.unpack_from(
"<HH", raw, first.header_offset + 26
)
data_offset = (
first.header_offset + zipfile.sizeFileHeader +
name_length + extra_length
)
raw[data_offset] ^= 1
with zipfile.ZipFile(io.BytesIO(raw)) as zf:
first = zf.infolist()[0]
try:
zf.read(first)
except zipfile.BadZipFile:
print("The first duplicate is corrupt")
print(zf.testzip())
Observed output:
The first duplicate is corrupt
None
testzip() should return "duplicate.txt".
Expected Behavior
Every member in infolist() should be validated individually. For duplicate names, testzip() should preserve the identity of each ZipInfo object and open the entry with:
self.open(zinfo, "r")
Rather than:
self.open(zinfo.filename, "r")
CPython versions tested on:
CPython main branch
Operating systems tested on:
Linux
Linked PRs
- gh-156540
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研究方向
從 ZipFile.testzip 開始,將其目前的項目開啟行為與 issue 中重複成員的 reproducer 進行比較。執行 reproducer 和相關的 zipfile 測試;完成的標準是逐一檢查每個 ZipInfo,並將較早的損毀重複項回報為 duplicate.txt。
由索引模型根據 Issue 內容生成。
評估
- 技術堆疊
- python
- 領域
- backend
- Issue 類型
- 缺陷
- 難度
- 2/5
- 預估耗時
- 1-3 小時
- 活躍度
- 停滯
- 描述清晰度
- 描述清楚
- 新手友好度
- 35/100