frozenset() created from a set literal is not untracked by the GC

gh-140232 made frozensets untracked by the GC when none of their elements can be tracked. However, the compiler's fast path for frozenset({...}) and frozenset({... for ...}) freezes the built set in place with _PySet_Freeze() (INTRINSIC_BUILD_FROZENSET), which skips that check, so the result stays tracked:

>>> import gc
>>> s = {1, 2}
>>> gc.is_tracked(frozenset(s))
False
>>> gc.is_tracked(frozenset({1, 2}))
True

I'm preparing a PR for this.

Linked PRs

• gh-155182

先使用 gc.is_tracked 从复现代码开始，然后检查名为 INTRINSIC_BUILD_FROZENSET 的编译器快速路径和 _PySet_Freeze()。当 frozenset({...}) 和 frozenset({... for ...}) 与 frozenset(s) 具有相同的跟踪行为，并且涵盖已报告的案例时，即表示完成。