frozenset() created from a set literal is not untracked by the GC

gh-140232 made frozensets untracked by the GC when none of their elements can be tracked. However, the compiler's fast path for frozenset({...}) and frozenset({... for ...}) freezes the built set in place with _PySet_Freeze() (INTRINSIC_BUILD_FROZENSET), which skips that check, so the result stays tracked:

>>> import gc
>>> s = {1, 2}
>>> gc.is_tracked(frozenset(s))
False
>>> gc.is_tracked(frozenset({1, 2}))
True

I'm preparing a PR for this.

Linked PRs

• gh-155182

Inizia con il riproduttore usando gc.is_tracked, quindi esamina il fast path del compilatore denominato INTRINSIC_BUILD_FROZENSET e _PySet_Freeze(). Il lavoro è completato quando frozenset({...}) e frozenset({... for ...}) hanno lo stesso comportamento di tracking di frozenset(s), con copertura per i casi segnalati.