The `bytearray()` value set to `bytes.partition()` and `bytes.rpartition()` is not converted to a `bytes()` value, keeping a `bytearray()` value in a tuple

Bug report

Bug description:

The bytearray() value set to bytes.partition() and bytes.rpartition() is not converted to a bytes() value, keeping a bytearray() value in a tuple as shown below:

v = bytes(b'ABCD')

                # ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓           # ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓
print(v.partition(bytearray(b'BC')))  # (b'A', bytearray(b'BC'), b'D')
print(v.rpartition(bytearray(b'BC'))) # (b'A', bytearray(b'BC'), b'D')
                 # ↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑          # ↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑

The bytearray() value set to bytes.partition() and bytes.rpartition() should be converted to a bytes() value, not keeping a bytearray() value in a tuple because they are bytes functions and because of readability and consistency as shown below:

v = bytes(b'ABCD')

                # ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓           # ↓↓↓↓↓
print(v.partition(bytearray(b'BC')))  # (b'A', b'BC', b'D')
print(v.rpartition(bytearray(b'BC'))) # (b'A', b'BC', b'D')
                 # ↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑          # ↑↑↑↑↑

In addition, the bytes() value set to bytearray.partition() and bytearray.rpartition() is converted to a bytearray() value, not keeping a bytes() value in a tuple as shown below:

v = bytearray(b'ABCD')

                # ↓↓↓↓↓↓↓↓↓↓↓↓                      # ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓
print(v.partition(bytes(b'BC')))  # (bytearray(b'A'), bytearray(b'BC'), bytearray(b'D'))
print(v.rpartition(bytes(b'BC'))) # (bytearray(b'A'), bytearray(b'BC'), bytearray(b'D'))
                 # ↑↑↑↑↑↑↑↑↑↑↑↑                     # ↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑

CPython versions tested on:

3.12

Operating systems tested on:

Windows

まず提供された Python の例を実行し、次に bytes.partition()、bytes.rpartition()、bytearray.partition()、bytearray.rpartition() の実装と、それらのテストを探します。完了条件は、返されるタプルの要素が、partitioning が呼び出された対象オブジェクトの型と一貫して一致し、両方向および両方の引数型について回帰テストがあることです。