with statement star target

Documentation

https://docs.python.org/3/reference/simple_stmts.html#grammar-token-python-grammar-target

According to the docs, the grammar for the with statement allows:

with_stmt                          ::= "with" with_stmt_contents
with_stmt_contents           ::= with_item
with_item                          ::= expression "as" target
target                                ::= identifier  | "*" target

from my understanding that would allow a python syntax like this:

class Test:
    def __enter__(self):
        return (1, 2)

    def __exit__(self, exc_type, exc_value, traceback):
        pass


with Test() as *mambo:
    print(mambo, type(mambo))

But for me with python version 3.12.8

I get a syntax error:

  File "/home/gringo/accessia/main/controller_start/test.py", line 9
    with Test() as *mambo:
                   ^^^^^^
SyntaxError: starred assignment target must be in a list or tuple

从所引用的 Python language-reference 中关于 with-statement 语法的章节开始，并在 Python 3.12.8 上复现该示例。将文档中描述的目标语法与报告的 SyntaxError 进行比较。当文档与观察到的行为得到协调，并且相关措辞或语法得到澄清时，即视为完成。