with statement star target

Documentation

https://docs.python.org/3/reference/simple_stmts.html#grammar-token-python-grammar-target

According to the docs, the grammar for the with statement allows:

with_stmt                          ::= "with" with_stmt_contents
with_stmt_contents           ::= with_item
with_item                          ::= expression "as" target
target                                ::= identifier  | "*" target

from my understanding that would allow a python syntax like this:

class Test:
    def __enter__(self):
        return (1, 2)

    def __exit__(self, exc_type, exc_value, traceback):
        pass


with Test() as *mambo:
    print(mambo, type(mambo))

But for me with python version 3.12.8

I get a syntax error:

  File "/home/gringo/accessia/main/controller_start/test.py", line 9
    with Test() as *mambo:
                   ^^^^^^
SyntaxError: starred assignment target must be in a list or tuple

Start with the referenced Python language-reference section on the with-statement grammar and reproduce the example on Python 3.12.8. Compare the documented target grammar with the reported SyntaxError. Done means the documentation and observed behavior are reconciled, with the relevant wording or grammar clarified.