Duck-typing in `inspect.getfile`
還沒有人認領這個 Issue。
- 主要語言
- Python
- 星號
- 77.2k
- 分支
- 36k
- PR 合併指標
- PR 指標待擷取
描述
Running inspect.getsource(numpy.random.random_sample) yields
File ~\.conda\envs\sage-dev\Lib\inspect.py:943, in getfile(object)
941 if iscode(object):
942 return object.co_filename
--> 943 raise TypeError('module, class, method, function, traceback, frame, or '
944 'code object was expected, got {}'.format(
945 type(object).__name__))
since the cython function is not correct recognized as a "true" function (i.e. it is not derived from FunctionType). But since a Cython function correct provides __code__, all the information is actually there to properly get the source file.
While it is quite possible to emulate the interface of functions in Cython's own function type, and recent Cython releases have seen several improvements here, the "inspect" module does not consider a Cython implemented function a "function", because it tests the object type explicitly instead of comparing an abstract interface or an abstract base class. This has a negative impact on code that uses inspect to inspect function objects, but would require a change to Python itself.
and
At the very least, the inspect module should use more duck-typing internally. For example, consider this code from "getfile":
if ismethod(object): object = object.__func__ if isfunction(object): object = object.__code__ if istraceback(object): object = object.tb_frame if isframe(object): object = object.f_code if iscode(object): return object.co_filename
Originally posted by @jdemeyer in #74257
Linked PRs
- gh-131632
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研究方向
從 inspect.getfile 以及 issue 中展示的 isfunction/iscode 檢查開始。比較公開 code 的物件是如何處理的,然後在進行任何工作之前檢視連結的 PR gh-131632。完成的標準是,所回報的 Cython 函式能夠解析其來源檔案,同時不破壞 inspect.getfile 既有的行為。
由索引模型根據 Issue 內容生成。
評估
- 技術堆疊
- python
- 領域
- devtools
- Issue 類型
- 功能
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- 4/5
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- 3-5 天
- 活躍度
- 停滯
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- 基本清楚
- 新手友好度
- 25/100