python / python/cpython

Duck-typing in `inspect.getfile`

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描述

Running inspect.getsource(numpy.random.random_sample) yields

File ~\.conda\envs\sage-dev\Lib\inspect.py:943, in getfile(object)
    941 if iscode(object):
    942     return object.co_filename
--> 943 raise TypeError('module, class, method, function, traceback, frame, or '
    944                 'code object was expected, got {}'.format(
    945                 type(object).__name__))

since the cython function is not correct recognized as a "true" function (i.e. it is not derived from FunctionType). But since a Cython function correct provides __code__, all the information is actually there to properly get the source file.

Refs: https://github.com/cython/cython/blob/030e3886fa094ecae6121f8ccacaf814956dca5c/docs/src/userguide/limitations.rst#L34

While it is quite possible to emulate the interface of functions in Cython's own function type, and recent Cython releases have seen several improvements here, the "inspect" module does not consider a Cython implemented function a "function", because it tests the object type explicitly instead of comparing an abstract interface or an abstract base class. This has a negative impact on code that uses inspect to inspect function objects, but would require a change to Python itself.

and

At the very least, the inspect module should use more duck-typing internally. For example, consider this code from "getfile":

    if ismethod(object):

        object = object.__func__

    if isfunction(object):

        object = object.__code__

    if istraceback(object):

        object = object.tb_frame

    if isframe(object):

        object = object.f_code

    if iscode(object):

        return object.co_filename

Originally posted by @jdemeyer in #74257

Linked PRs
  • gh-131632

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调研方向

从 inspect.getfile 以及 issue 中展示的 isfunction/iscode 检查开始。比较公开 code 的对象是如何处理的,然后在进行任何工作之前审查链接的 PR gh-131632。完成的标准是,所报告的 Cython 函数能够解析其源文件,同时不破坏 inspect.getfile 现有的行为。

由索引模型根据 Issue 内容生成。

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