Exception that calls `super().__init__` breaks `copy.copy`

Bug report

Bug description:

For some reason calling Exception.__init__ breaks copy.copys ability to detect args. The following code

import copy

class MyException(Exception):
    def __init__(self, x):
        super().__init__()
        self.x = x

my_exc = MyException(5)
copy.copy(my_exc)

gives

Traceback (most recent call last):
  File "./foo.py", line 9, in <module>
    copy.copy(my_exc)
  File "/usr/lib/python3.12/copy.py", line 97, in copy
    return _reconstruct(x, None, *rv)
           ^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "/usr/lib/python3.12/copy.py", line 253, in _reconstruct
    y = func(*args)
        ^^^^^^^^^^^
TypeError: MyException.__init__() missing 1 required positional argument: 'x'

Removing the super().__init__() line makes everything work as expected, but given that it's generally seen as good practice to call super().__init__() in child classes, and you may be working with a more complex class structure, this seems like pretty bad behavior.
I haven't dug deep enough into copy.copy or BaseException.__init__ to decide which one deserves the blame.

For the reason why I want to copy exceptions, see https://github.com/python-trio/flake8-async/issues/298

CPython versions tested on:

3.9, 3.10, 3.11, 3.12, 3.13, 3.14

Operating systems tested on:

Linux

Reproduisez l’exemple avec copy.copy et examinez le comportement dans /usr/lib/python3.12/copy.py avec BaseException.init. Déterminez le comportement de copie attendu pour une Exception dont l’initialiseur appelle super().init(), puis ajoutez un test de régression montrant que la copie préserve l’état requis du constructeur sans lever de TypeError.