BUG: using `pytask.task()(func_defined_in_other_file)` doesn't work

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• I have confirmed this bug exists on the latest version of pytask.
• (optional) I have confirmed this bug exists on the main branch of pytask.

Code Sample, a copy-pastable example

zipped dir: tasks.zip

# lib.py
def get_name():
    return "jane"

# task_bug.py
from pathlib import Path

import pytask

from .lib import get_name

task_get_name = pytask.task(produces=Path("name.txt"))(get_name)

Problem description

It appears that inpytask.task(), the created task is stored in COLLECTED_TASKS,
but is stored under COLLECTED_TASKS["lib.py"] (the place where the function was defined), not under COLLECTED_TASKS["task_bug.py"] (where the task was created). Then, when we actually go looking through COLLECTED_TASKS for tasks to execute, we miss it because we only look under "task_bug.py"

Expected Output

I think the created task should be stored under COLLECTED_TASKS["task_bug.py"] where the task was created.

Start with the pytask.task() decorator and trace how the function from lib.py is registered when called in task_bug.py. Inspect the COLLECTED_TASKS lookup path and the tasks.zip reproduction; done means the task is discovered under task_bug.py and executes with the expected output.