Consider re-ordering Array#reduce overloads in lib.d.ts

Example code:

type UnaryFunction = (arg1) => any;
type BinaryFunction = (arg1, arg2) => any;

let binaryFuncs: BinaryFunction[] = [];
let unaryFunc = arg1 => {};
let reduced = binaryFuncs.reduce((prev, next) => prev, unaryFunc);

// ACTUAL:
let f: UnaryFunction = reduced;     // ERROR binary not assignable to unary

// EXPECTED:
let f: UnaryFunction = reduced;     // OK - both lhs and rhs really are unary

The call to Array#reduce in the above example definitely returns a unary function, but the type system erroneously infers the return type as a binary function.

This seems to be caused by the declaration order of the two overloads of Array#reduce in lib.d.ts. If the declaration order is reversed, the problem is solved.

The two overloaded declarations in lib.d.ts are as follows:

reduce(callbackfn: (previousValue: T, currentValue: T, currentIndex: number, array: T[]) => T, initialValue?: T): T;
reduce<U>(callbackfn: (previousValue: U, currentValue: T, currentIndex: number, array: T[]) => U, initialValue: U): U;

The first overload matches the example with T=BinaryFunction, since it satisfies the compiler's assignability checks. So the second overload is never considered, even though it is a strictly better match, with T=BinaryFunction and U=UnaryFunction.

Would it be possible to swap the overload order for Array#reduce (and Array#reduceRight) in lib.d.ts to resolve this issue?

lib.d.ts で、2 つの Array#reduce のオーバーロードと、それに対応する Array#reduceRight のオーバーロードを見つけます。issue の例を再現し、その後、オーバーロードの順序を逆にすると、両方のメソッドで推論された結果を UnaryFunction に代入できることを確認します。