Allow primitive LHS to `instanceof` operator if RHS is a custom `hasInstance`

### 🔎 Search Terms

in:title instanceof

### 🕗 Version & Regression Information

- This changed between versions 5.2 and 5.3
- This changed in commit or PR #55052

### ⏯ Playground Link

https://www.typescriptlang.org/play/?#code/IwAglgdgzgLghhAxgUwPYDMQG8QG0DKAngLYBGqANgHQAWcUAktPEsgLoAUAlNiAE7IYAVz4QQMPkOQgAvjICwAKAD0ykAD0QAFRrSKydDAC0dCABMQUMGekYQCEAHJIsBCgyOQyAB4AHAVBWqGLEQrAgpLaYMIS+0o4IhI4ANPZiqKQAVsiIMOKxtnz2+XEgvnB8cMSCyHxUHABMAMwArAAcXEA

### 💻 Code

```ts
1 instanceof { [Symbol.hasInstance]() { return true }}
```

### 🙁 Actual behavior

Error: The left-hand side of an 'instanceof' expression must be of type 'any', an object type or a type parameter.(2358)

### 🙂 Expected behavior

No errors

### Additional information about the issue

For custom 'Symbol.hasInstance' methods, `number instanceof obj` can return true or false according to implementation.

Start with the linked TypeScript Playground reproduction and compare the reported behavior for `1 instanceof { [Symbol.hasInstance]() { return true }}` with the expected result. Trace the type-checking path for `instanceof` expressions, then add coverage showing that a primitive left-hand side is accepted when the right-hand side defines a custom `Symbol.hasInstance`.

Written by the indexing model from the issue text.