ES `ClassDecoratorContext.name` has incorrect value with static `name`

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### 🔎 Search Terms

ClassDecoratorContext static name

### 🕗 Version & Regression Information

5.0.4-5.9.3

### ⏯ Playground Link

https://tsplay.dev/N7vAow

### 💻 Code

```ts
const decorate = (_: unknown, ctx: ClassDecoratorContext) => {
console.log('decorate(%o)', ctx.name);
};

@decorate
class A {
static get name() {
return 2434;
}
}
```

### 🙁 Actual behavior

`ctx.name` is `2434` (from `A.name`)

### 🙂 Expected behavior

`ctx.name` is `'A'` (actual class name)

### Additional information about the issue

The wrong value comes from the context initializer in the emitted code:

```ts
__esDecorate(
null,
(_classDescriptor = { value: _classThis }),
_classDecorators,
{ kind: 'class', name: _classThis.name, metadata: _metadata },
null,
_classExtraInitializers,
);
```

The context `name` is initialized with `_classThis.name` (which triggers the getter) instead of the actual class name value (literal `"A"` in this case).

## Possible Fix

Currently, the `_classThis.name` fragment comes from `const classNameReference` in `transformClassLike` in `transformers/esDecorators.ts`:

```ts
const classNameReference = factory.createPropertyAccessExpression(renamedClassThis, "name");
```

It should be adjusted to get an actual class name (either literal or computed), possibly like this:

```ts
const classNameReference = node.name ? factory.createStringLiteralFromNode(node.name) :
node.emitNode?.assignedName ?? factory.createStringLiteral("")
```

Inizia in transformers/esDecorators.ts, in transformClassLike, e verifica come viene costruito classNameReference per il contesto del decoratore di classe. Riproduci il problema con il playground collegato, quindi verifica che una classe con un getter statico di name fornisca a ctx.name il suo nome effettivamente dichiarato, ad esempio "A", invece del risultato del getter.

Scritto dal modello di indicizzazione a partire dal testo della issue.