ES `ClassDecoratorContext.name` has incorrect value with static `name`

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### 🔎 Search Terms

ClassDecoratorContext static name

### 🕗 Version & Regression Information

5.0.4-5.9.3

### ⏯ Playground Link

https://tsplay.dev/N7vAow

### 💻 Code

```ts
const decorate = (_: unknown, ctx: ClassDecoratorContext) => {
console.log('decorate(%o)', ctx.name);
};

@decorate
class A {
static get name() {
return 2434;
}
}
```

### 🙁 Actual behavior

`ctx.name` is `2434` (from `A.name`)

### 🙂 Expected behavior

`ctx.name` is `'A'` (actual class name)

### Additional information about the issue

The wrong value comes from the context initializer in the emitted code:

```ts
__esDecorate(
null,
(_classDescriptor = { value: _classThis }),
_classDecorators,
{ kind: 'class', name: _classThis.name, metadata: _metadata },
null,
_classExtraInitializers,
);
```

The context `name` is initialized with `_classThis.name` (which triggers the getter) instead of the actual class name value (literal `"A"` in this case).

## Possible Fix

Currently, the `_classThis.name` fragment comes from `const classNameReference` in `transformClassLike` in `transformers/esDecorators.ts`:

```ts
const classNameReference = factory.createPropertyAccessExpression(renamedClassThis, "name");
```

It should be adjusted to get an actual class name (either literal or computed), possibly like this:

```ts
const classNameReference = node.name ? factory.createStringLiteralFromNode(node.name) :
node.emitNode?.assignedName ?? factory.createStringLiteral("")
```

Comienza en transformers/esDecorators.ts, en transformClassLike, e inspecciona cómo se construye classNameReference para el contexto del decorador de clase. Reproduce el problema con el playground enlazado y, a continuación, verifica que una clase con un getter estático de name proporcione a ctx.name su nombre declarado real, como "A", en lugar del resultado del getter.

Escrito por el modelo de indexación a partir del texto del issue.