Generic syntax ambiguity is handled incorrectly

🔎 Search Terms

generic syntax ambiguity

🕗 Version & Regression Information

• I was unable to test this on prior versions because there is no online tooling for it

⏯ Playground Link

https://www.typescriptlang.org/play/?#code/MYewdgzgLgBAhjAvDAjAGhgIyTATB4HAZgwBMcAWDAUxwFYBuAKFEhABtqA6dkAcwAUCADxYMAwgD4YA8gDIY1AJQrmQA

💻 Code

const a = 1, b = 2, c = 3, d = 4, e = 5;
console.log(a < b, (c > (d & e)));

🙁 Actual behavior

This expression is not callable.

🙂 Expected behavior

true false

Additional information about the issue

While there might be some justification for why

const a = 1, b = 2, c = 3, d = 4, e = 5;
console.log(a < b, c > (d & e));

doesn't work as it did in JS, in the provided example there isn't even any disambiguity.

Reproduisez l’expression signalée dans le TypeScript Playground lié et comparez-la à la version sans parenthèses. Suivez la manière dont le compilateur gère l’ambiguïté de la syntaxe générique pour cette expression ; le travail est terminé lorsque le code fourni est accepté et produit true false sans régression pour la forme ambiguë associée.