microsoft / microsoft/TypeScript
Generators can return undefined values
@rbuckton がすでに取り組んでいます。
2024年9月13日 から。
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説明
Summary
Should the return type of yield* a be TReturn | undefined when in strict mode as opposed to TReturn (where TReturn is the value of the TReturn type argument to a's Iterable type instantiation)?
Or should the type of IteratorReturnResult.value be changed to TReturn | undefined when in strict mode (and potentially the type of Generator.return(value: TReturn) be relaxed to Generator.return(value?: TReturn))?
Have you considered these scenarios? (A github microsoft site search for "generator return undefined" yields no results).
Background
Generators will return undefined values when:
next()is called after the generator has already returned its return value:
function* gen(): Generator<number, string> {
yield 42;
return "done";
}
const a = gen();
console.log(a.next()); // { value: 42, done: false }
console.log(a.next()); // { value: 'done', done: true }
console.log(a.next()); // { value: undefined, done: true }
2.1) the generator is interrupted via a break statement of for-of loop on the generator
const nestedIterableIterator: IterableIterator<string, string, unknown> = {
[Symbol.iterator]() { return this; },
next() {
return { value: "42", done: false }
},
return(value: string) {
console.log("return called with", value);
return { value, done: true }
}
}
function* generator() {
yield* nestedIterableIterator;
return "never";
}
const it = generator();
it.next();
it.return("passthrough"); // return called with passthrough
for (const x of generator()) {
break; // return called with undefined
}
2.2) the generator is manually interrupted by calling its return method without arguments:
function* gen(): Generator<number, string> {
yield 42;
yield 43;
return "done";
}
const a = gen();
console.log(a.next()); // { value: 42, done: false }
console.log(a.return(undefined as unknown as string)); // { value: undefined, done: true }
console.log(a.next()); // { value: undefined, done: true }
- The generator is attempted to be iterated over using
yield*after it has already returned:
function* gen(): Generator<number, string> {
return "done";
}
function* consumer() {
const a = gen();
console.log(yield* a); // done
console.log(yield* a); // undefined
}
consumer().next();
Effect
The type signature of Generator.return guards against 2.2, and there is no way to get the return value from a for-of loop.
That leaves scenarios 1 and 3, of which 1 is likely uncommon, 3 is probably the only viable scenario and only in the case of user error...
⚙ Compilation target
ES2015
⚙ Library
lib.es2015.generator.d.ts
Missing / Incorrect Definition
Generator.return and IteratorReturnResult.value
Sample Code
See above.
Documentation Link
No relevant documentation.
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