microsoft / microsoft/TypeScript
Conditionally optional/conditionally readonly properties
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説明
Conditionally-Optional Properties (in object types and interfaces)
🔍 Search Terms
- conditionally optional
- conditional optional
- conditionally readonly
- conditional readonly
These issues are related, but not exactly the same:
- #36126
- #31409
✅ Viability Checklist
My suggestion meets these guidelines:
- This wouldn't be a breaking change in existing TypeScript/JavaScript code
- This wouldn't change the runtime behavior of existing JavaScript code
- This could be implemented without emitting different JS based on the types of the expressions
- This isn't a runtime feature (e.g. library functionality, non-ECMAScript syntax with JavaScript output, new syntax sugar for JS, etc.)
- This feature would agree with the rest of TypeScript's Design Goals.
⭐ Suggestion / 📃 Motivating Example
A new syntax and associated type-checking making it possible to mark a property as "conditionally-optional", for example:
interface Calculate<T> {
items: T[];
/**
* Converts an item into a string for comparison.
* If `T` is already a string type, this is optional.
*/
getKey(? if T extends string): (item: T) => string;
}
the intent here is that getKey is optional if T is string or a subtype of string, but otherwise getKey is mandatory. Thus, an implementation could (for example) provide a default implementation getKey = str => str.
It's currently possible to write types that accomplish this using a mixture of intersections and conditionally-mapped types. However, you lose certain important ergonomic attributes:
- the syntax for intersection types, mapped types, and conditional types is much more complicated and much less familiar than interface/object types
- conditional types and complex mappings are likely to lose jsdoc comments, defeating intellisense when developers are later trying to use the type
- complex types can't be
extended whereas interfaces and object types can be
💻 Use Cases
In general, any attribute of a property could be made conditional in the same way:
type Example = <T, Flag extends boolean, Active extends boolean> = {
// conditionally optional:
convertToString (? if T extends string): (item: T) => string;
// optional; made conditionally required:
initialValue? (-? if T extends boolean): T;
// conditionally readonly:
(readonly if Flag extends "permanent") flagValue: boolean;
// conditionally defined:
(parentId if Active extends true): string;
}
In most cases, a basic (but incomplete) workaround exists: use the less-restrictive form everywhere. For example, if it's going to mostly be used and you don't want to forget to pass a property, just make it required; if it's mostly going to be accessed and you don't want to forget that a property is present, just make it optional, etc.
Allowing these values to be set conditionally would just make it easier to express certain more-complex domain-specific constraints, while keeping the types mostly self-contained and readable.
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調査の方向性
まず関連する issue #36126 と #31409 を確認し、次に提案された構文を、ここで説明されている conditional、mapped、intersection type の回避策と比較します。実装のスコープを決めるには、条件付きで optional、required、readonly、defined となるプロパティの設計について合意する必要があります。
索引モデルが issue の本文から書いたものです。
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- compilers
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