Parameter types not being inferred in a class method whose type is indexed from an interface

TypeScript Version: 3.7.4

Search Terms:
Index type
Parameter type of method
Inferring parameter types

Code

interface Parameters1 {
   paramA: number;
   paramB: string;
}

interface Parameters2 {
   paramC: boolean;
}

interface SomeFunctions {
   foo(options: Parameters1): void;
   bar(options: Parameters2): void;
}

class AClass implements SomeFunctions {
   public foo(options: Parameters1): void { }

   public bar(options: Parameters2): void { }
}

const aClassInstance = new AClass();

function callMethod<K extends keyof SomeFunctions>(
   methodName: K,
   options: Parameters<SomeFunctions[K]>[0]
) {
   // 1. Does not work: 
   // Argument of type 'Parameters<SomeFunctions[K]>[0]' is not assignable to parameter of type 'Parameters1 & Parameters2'.
   aClassInstance[methodName](options);
  
   // 2. Also does not work
   // Argument of type 'Parameters<SomeFunctions[K]>[0]' is not assignable to parameter of type 'Parameters1 & Parameters2'.
   // Type 'Parameters<SomeFunctions[K]>[0]' is not assignable to type 'Parameters1'.
   (aClassInstance[methodName] as SomeFunctions[K])(options);

   // 3. Does work, even though it is essentially the same thing as 2
   type MethodType = (o: typeof options) => ReturnType<SomeFunctions[K]>
   (aClassInstance[methodName] as MethodType)(options);
}

Expected behavior:

Case 2 should work. Possibly also case 1.
Typescript should know that options is the correct type

Actual behavior:

Only case 3 works, even though it is more or less the same as case 2

Playground Link:

Playground

Related Issues:

TypeScript Playground の再現から始め、callMethod 内の 3 つの呼び出しを比較します。特に、ケース 1 と 2 を動作するケース 3 と比較してください。コンパイラーがケース 2、場合によってはケース 1 も受け入れ、インデックス付きメソッドに対して期待されるパラメーターの関係を維持できれば、Issue は完了です。