Allow using type parameters and return types with overloaded class constructors

Search Terms

Generic Class Constructor Declaration Overloads Type Parameters

Suggestion

This is partially a request to revisit some of the discussion from here:
https://github.com/microsoft/TypeScript/issues/10860
But it's also to provide some examples of cases that are difficult/impossible to type using classes today.

A class may frequently assign different types to its properties depending on how it was instantiated. While we can type those properties as unions of all their possible types (or even use completely separate classes), it would be amazing if we could "narrow" a class's type based on how it was instantiated.

We CAN handle this type of complexity with regular function overloads, because the relevant call signature is narrowed by both function parameters and type parameters. Class constructors, however, only pay attention to the parameters being passed and can't have type parameters.

Use Cases

// Using type parameters with overloaded generic function
function func(): void;
function func<T extends string>(requiredThing: T): void
function func(requiredThing?: string) { }
func()              // Ok
func<'hello'>()     // Expects 1 argument, as expected

// Attempting to use type parameters with overloaded class constructor
class Example<T> {
    constructor()
    constructor(blah: T)    // How do we connect this to the presence of T?
    constructor(blah?: T) {}
}
new Example()           // Ok
new Example<'hello'>()  // We want this to expect 1 argument somehow

As was also discussed in https://github.com/microsoft/TypeScript/issues/10860, return types on a constructor could theoretically represent narrowed versions of the instance type. Currently there's not an easy way to narrow a property's type based on how the class was instantiated:

class Example {
    prop?: string | number

    constructor()    // When this is used, prop should be string | number | undefined
    constructor(prop: string)    // When this is used, prop should be string
    constructor(prop: number) // When this is used, prop should be number
    constructor(prop?: string | number) {
        // implementation
    }
}

Examples

Ideally, maybe something like this for narrowing by type parameters:

class Example {
    constructor()
    constructor<T extends string>(blah: T)
    constructor(blah?: string) {}
}
new Example()           // Ok
new Example<'hello'>()  // Would expect 1 argument

And maybe something like this for return types:

interface IExampleString extends Example {
    prop: string
}
interface IExampleNumber extends Example {
    prop: number
}
class Example {
    prop?: string | number

    constructor()    // When this is used, prop should be string | number | undefined
    constructor(prop: string): IExampleString    // When this is used, prop should be string
    constructor(prop: number): IExampleNumber    // When this is used, prop should be number
    constructor(prop?: string | number) {
        // implementation
    }
}

Checklist

My suggestion meets these guidelines:

• This wouldn't be a breaking change in existing TypeScript/JavaScript code
• This wouldn't change the runtime behavior of existing JavaScript code
• This could be implemented without emitting different JS based on the types of the expressions
• This isn't a runtime feature (e.g. library functionality, non-ECMAScript syntax with JavaScript output, etc.)
• This feature would agree with the rest of TypeScript's Design Goals.

Không có tệp triển khai, bài kiểm thử hoặc điểm vào nào được nêu. Hãy bắt đầu bằng việc xem lại cuộc thảo luận được liên kết trong issue 10860 và các ví dụ về overload constructor ở đây. Để được coi là hoàn tất, cần có ngữ nghĩa đã được thống nhất và hỗ trợ triển khai cho các tham số kiểu cũng như việc thu hẹp kiểu trả về trên các constructor của lớp bị overload, cùng với các bài kiểm thử tương ứng.