ipympl for matplotlib not created through pyplot

Is it possible to use ipympl starting from an arbitrary matplotlib figure? If yes, an example would be helpful. Thanks!

Use Case: I would like to use ipympl for SageMath plots. The later do have a method to
convert them to matplotlib figure. However the figure has not been created with the usual
pyplot workflow, and does not have a canvas setup.

In a jupyter notebook with the SageMath kernel (e.g. using the binder link from https://github.com/sagemath/sage-binder-env/ after installing ipympl with sage -pip install ipyml)

%matplotlib widget
p = plot(sin(x))
fig = p.matplotlib();
type(fig.canvas)
<class 'NoneType'>

It could well be that SageMath is producing weird matplotlib figures though.

cc: @zerline

Non vengono indicati file del progetto o test. Inizia riproducendo lo snippet del notebook Jupyter con la figura matplotlib prodotta da SageMath e verifica se ipympl può fornire un canvas per essa; il lavoro è completato quando è stato stabilito se questo workflow funziona e sono stati documentati un esempio minimo o la limitazione.