@SubclassMapping selecting implementation class based on source field value

Personne n'a encore pris cette issue.

### Use case

It is common practice saving multiple sub-classes into one database tables. E.g.:
I have a db entity Contact with type field value
```kotlin
@Entity
@Table(name = CONTACTS_TABLE)
open class ContactEntity {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
var id: Long = 0

@Column(name = CONTACT_TYPE_COLUMN, nullable = false)
var type: ContactType = ContactType.BUSINESS
}
```
My domain model Contact is abstract and can have two implementations: BusinessContact and NaturalPersonContact:
```kotlin
sealed interface Contact {
val id: Long
}

data class BusinessContact(
override val id: Long,
val businessName: String,
) : Contact

data class NaturalPersonContact(
override val id: Long,
val firstName: String,
val lastName: String,
) : Contact
```
Trying to define a Mapper with `@SubclassMapping` has no option to add logic to it based on type property:
```kotlin
@SubclassMapping(target = BusinessContact::class, source = ContactEntity::class)
@SubclassMapping(target = NaturalPersonContact::class, source = ContactEntity::class)
fun entityToDomainModel(entity: ContactEntity): Contact
```

### Generated Code

_No response_

### Possible workarounds

None known

### MapStruct Version

implementation("org.mapstruct:mapstruct:1.5.5.Final")

Commencez par examiner comment @SubclassMapping est traité pour le mapper ContactEntity-to-Contact décrit dans l’issue, y compris le comportement de MapStruct 1.5.5.Final. L’implémentation doit permettre de sélectionner BusinessContact ou NaturalPersonContact à partir de la propriété du type source et inclure une couverture pour ce mapping généré.

Rédigé par le modèle d'indexation à partir du texte de l'issue.