@SubclassMapping selecting implementation class based on source field value

Use case

It is common practice saving multiple sub-classes into one database tables. E.g.:
I have a db entity Contact with type field value

@Entity
@Table(name = CONTACTS_TABLE)
open class ContactEntity {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    var id: Long = 0

    @Column(name = CONTACT_TYPE_COLUMN, nullable = false)
    var type: ContactType = ContactType.BUSINESS
}

My domain model Contact is abstract and can have two implementations: BusinessContact and NaturalPersonContact:

sealed interface Contact {
    val id: Long
}

data class BusinessContact(
    override val id: Long,
    val businessName: String,
) : Contact

data class NaturalPersonContact(
    override val id: Long,
    val firstName: String,
    val lastName: String,
) : Contact

Trying to define a Mapper with @SubclassMapping has no option to add logic to it based on type property:

    @SubclassMapping(target = BusinessContact::class, source = ContactEntity::class)
    @SubclassMapping(target = NaturalPersonContact::class, source = ContactEntity::class)
    fun entityToDomainModel(entity: ContactEntity): Contact

Generated Code

No response

Possible workarounds

None known

MapStruct Version

implementation("org.mapstruct:mapstruct:1.5.5.Final")

Comience examinando cómo se procesa @SubclassMapping para el mapper ContactEntity-to-Contact descrito en el issue, incluido el comportamiento de MapStruct 1.5.5.Final. La implementación debe permitir seleccionar BusinessContact o NaturalPersonContact a partir de la propiedad del tipo fuente e incluir cobertura para ese mapping generado.