Lacking arguments in array.sort()'s compareFn

Hello, I found this weird usage in test [Shuffle an array](https://javascript.info/array-methods#shuffle-an-array)'s "simple solution":


There is just no arguments in the `array.sort()`'s `compareFn`:
```js
array.sort(() => Math.random() - 0.5);
```

But [MDN](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort#parameters) says if we use `compareFn`, the arguments of `compareFn` "Will never be undefined.":


According to MDN, the `compareFn` must be used with arguments, i.e.
```js
array.sort((a, b) => Math.random() - 0.5);
```

If it is a typo indeed, please fix it at your convenience, thank you.

從 issue 中連結的「Shuffle an array」區段開始，在教學的原始碼中搜尋所顯示的 array.sort() 範例。對照所參照的 MDN 文件確認 compareFn 的措辭，如果範例中有拼字錯誤，就更新範例，並確認教學顯示的是修正後的程式碼片段。

由索引模型根據 Issue 內容生成。