Lacking arguments in array.sort()'s compareFn

Hello, I found this weird usage in test [Shuffle an array](https://javascript.info/array-methods#shuffle-an-array)'s "simple solution":


There is just no arguments in the `array.sort()`'s `compareFn`:
```js
array.sort(() => Math.random() - 0.5);
```

But [MDN](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort#parameters) says if we use `compareFn`, the arguments of `compareFn` "Will never be undefined.":


According to MDN, the `compareFn` must be used with arguments, i.e.
```js
array.sort((a, b) => Math.random() - 0.5);
```

If it is a typo indeed, please fix it at your convenience, thank you.

从 issue 中链接的“Shuffle an array”部分开始，在教程源代码中搜索所示的 array.sort() 示例。对照所引用的 MDN 文档确认 compareFn 的措辞，如果示例中存在拼写错误则更新示例，并验证教程显示的是修正后的代码片段。

由索引模型根据 Issue 内容生成。