Obeserve not works when showing result in widgets.Output()

I want to display the observe function result in widgets.Output() instead of current frame.
So I tried two ways.
1.
data_output = widgets.Output()
def show_dataframe(change):
with data_output:
clear_output()
display(data_frame.iloc[change['new']][:10])
js2py_memory.observe(show_dataframe, names=["data"])

2.
data_output = widgets.Output()
def show_dataframe(change):
clear_output()
display(data_frame.iloc[change['new']][:10])
with data_output:
js2py_memory.observe(show_dataframe, names=["data"])

Both two ways cannot change the display location of observe.

Is there any ways that I can display the result in output?

Reproduce the two snippets using js2py_memory.observe, widgets.Output(), clear_output(), and display() to confirm where the callback output appears. Read the observer and output-widget entry points involved in this behavior; done means the observed dataframe result renders inside data_output rather than in the current frame.

Do mô hình lập chỉ mục viết ra từ nội dung của issue.