Calling show on a visible element modifies the display type to block, despite it being flex

I encountered some unwanted behavior when using show/hide to filter a list of elements specifying _display:flex_.

When calling the correct sequence everything works OK. So calling _hide_ first seems to register the original display type before setting _display:none_. Then after calling _show_, _display:flex_ is restored.

Calling _show_ on an element that is already visible causes the display type to change to _block_. And it never reverts to _flex_ in my case. This causes undesired changes to the layout. Ideally this method should have no effect in this case.

I've worked around this to make sure _show_ is never called on visible elements, but I think this should be default behavior.

PS. The docs state that show/hide switches between none and block. But this is obviously not the case since it also switches to flex.

Comienza localizando la implementación de show/hide y reproduciendo la secuencia reportada con un elemento cuyo display sea flex. Verifica que llamar a show sobre un elemento que ya es visible deje sin cambios su tipo de display, mientras que el comportamiento existente de hide-then-show siga restaurando flex.

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